mekentosj.com | Solutions Widget

Solutions: The Solution!: Sometimes being a scientist is not as great as it may seem: making solutions. What mass (m) of a chemical with a molecular weight (M.W.) of 121.5 g/mole do you need to make a solution with a volume (V) of 250 ml and a molarity (M) of 1.5 mM? Solutions is THE solution for this calculation. Enter the values you have and let this widget do the rest for you by hitting the bubble of the desired unit on the bottom of the widget.

Screenshots

Make-up: The background image of the widget was created with the help of this wonderfull Photoshop tutorial. For the layout of the background image of the back we used an other tutorial from Alex Edelman. Many thanks for both tutorials.

Avogadro's number: Amedeo Avogadro (1776 - 1856) was an Italian chemist and physicist, most noted for his contributions to the theory of molarity and molecular weight. Avogadro's number (the number of molecules in one mole: 6.02214199 * 10²³) is named in his honor, as is Avogadro's law. Avogadro's number is also called Avogadro's constant (N_A) used in chemistry and physics. Avogadro's number is formally defined as the number of carbon-12 atoms in 12 grams (0.012 kg) of carbon-12, which is approximately 6.022 * 10²³. A mole is defined as Avogadro's number of particles of any kind of substance (atoms, ions, molecules, or formula units).; Source:WikipediA >>

Online Solutions

Calculate the molarity of water by pushing the M-button on the lower right, or fill in values for three units of your own solution and calculate the fourth.

	g/mole